I’m using an LG K9 right now. Works ok, but I’d prefer a smaller screen

Did you know YAML is a recursive acronym? It stands for ‘YAML AML MAML LAML’

Getting XCom flashbacks. I’d set up a breach team on the door, and send the rest of the squad round and up that drainpipe so they can drop down from the roof. But best go around the back of the cars so as not to activate through the window.

Hello!

Your link is to https://pixel.mamutut.space/p/wowwoweowza/621370665154999687 which is not actually the picture, but a web page that includes the picture (plus some other elements). Some web pages include metadata that lets services like Lemmy pull out the relevant image, but that isn’t present or isn’t working correctly here, so we don’t see the picture.

If you click the picture at your link, it takes you to the picture itself at https://pixel.mamutut.space/storage/m/_v2/621369676392719750/f1538e3aa-7b3151/3hhaJedYNkCy/Pu8IxA7M4OKDSRYvr01WzyNJEwv0IkEVL96Bjziu.jpg . If you replace the URL in your post with this one, it should work as you expect.

Isn’t it more like, a guy who wanted to kill the Queen talked to a chatbot about it, and the chatbot rolled with it cos chatbots will default to rolling with whatever you give them? Just seems the likely scenario to me …

Yep, this BBC article has a couple of the chat logs. If they’re representative, the bot is no more culpable than if he asked a magic 8-ball.

Alien is a stupid name for an alien when you stop to think about it. Just like with the creature in Frankenstein, people are going to grab at any alternate name presented, cos it’s just too awkward to talk about otherwise.

Enough with that! You can’t question the trolley situation, it’s been like this for generations. Get on board. We have flags!

Oh no! I knew this would be controversial.

Good point. It has zero contact force at the apex, so 14m is an upper bound on possible cat-loops.

The cat is moving in a circle, so it has a centripetal acceleration and a centripetal force. At the apex of the loop, that force is the sum of gravity, and resistance from the track. The track force is greater than or equal to zero, so acceleration due to gravity is less than or equal to the total centripetal acceleration.

g ≤ v²/r
So,
r ≤ v²/g

Taking top speed of a cat as 8.278m/s (from Wolfram Alpha), and g on earth as 9.81m/s², this gives us r ≤ 6.99m. So long as the cat can maintain its top speed all around the loop, it can successfully do a loop of up to 14 meters diameter. This is a lot bigger than I expected, to the extent that I suspect some flaw in my reasoning.

2nd of Dodecember

Your less thans got HTML-escaped into < and I spent embarrassingly long trying to figure out what pointer magic you were demonstrating

Thanks. This was useful context.

Blåhaj are the best. If you’ve got a problem with Blåhaj you’ve got a problem with me.